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Interrupt is blocked by function!


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wewa

Fri Jul 11 2008, 01:34AM

Registered Member #8956

Joined: Fri Jul 11 2008, 01:23AM

Posts: 10
Thanked 1 time in 1 posts

Hi!

I've got the problem, that if I declare a variable in a function, the interrupt is blocked.

CODE:

#include <18F4525.h>

#fuses HS,NOWDT,NOPROTECT,NOLVP

#use delay(clock=20000000)

#use rs232(baud=19200, xmit=PIN_C6, rcv=PIN_C7, ERRORS, stream=PC)

int1 function() {

int32 cnt;  /*This seems to block the INTERRUPT #INT_RDA - But why?*/

while(1) {

}

} //END function

#INT_RDA

void seriell() {

char c;

c=getc(PC);

output_high(pin_b4);

} //END seriell

void main() {

ENABLE_INTERRUPTS(INT_RDA);      //serieller Empfang

ENABLE_INTERRUPTS(Global);

function();

   while (1) {

   } //END while

} //END main

Why does the declaration of a variable in a function block the interrupt?

PS: I use the CCS C Compiler with MPLAB and a PIC18F4525.

Ajay

Fri Jul 11 2008, 08:19AM

Rickey's World Admin

Registered Member #1

Joined: Fri Feb 24 2006, 04:56AM

Posts: 4035
Thanked 751 times in 710 posts

I really don't know what you're trying to do in your program..

But i think you need to remove this from your function to make your program work perfectly, even along with variable declaration.

CODE:

while(1) {

}

If that does not solve your problem can you explain me what you mean by blocking your interrupt and symptoms of your program when it is running with variable deceleration?

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wewa

Fri Jul 11 2008, 09:20AM

Registered Member #8956

Joined: Fri Jul 11 2008, 01:23AM

Posts: 10
Thanked 1 time in 1 posts

sorry, the problem was somewhere else

In #INT_TIMER3 a function was called which waited on a action to be taken in #INT_RDA. And I think this was too much for the PIC.

But thanks for your help.

Problem solved.

PS: The while(1)-Loop is no problem, its not blocking an Interrupt.
With "blocking interrupt" I meant that something impeded that the µC jumped to the interrupt.