isolating two blocks from eachother
Discussion in "Electronics" started by Kazim Feb 2, 2009.
Mon Feb 02 2009, 01:38 pm
my problem is that i'm using two voltage dividers in a circuit ..... both r getting effected by each other.... is there any way that i could isolate them from each other..... i've explained the matter in a better way in the image.....
the frequency of the square wave is 300bps.....
plz help....and keep it as simple as possible and briefly explain the solution too..... thanks
problem 2:
at some other place i've a 300bps square wave which has 2.5V as lo and 3V as hi..... i want to change it to a 0-5 square wave..... how would i achieve this???? i thought of achieving it in two steps... first bring the lo voltage back to 0V, like remove the DC component and then amplify it to 5V using a single supply op amp...... plz comment if there is a better solution.....
the frequency of the square wave is 300bps.....
plz help....and keep it as simple as possible and briefly explain the solution too..... thanks
problem 2:
at some other place i've a 300bps square wave which has 2.5V as lo and 3V as hi..... i want to change it to a 0-5 square wave..... how would i achieve this???? i thought of achieving it in two steps... first bring the lo voltage back to 0V, like remove the DC component and then amplify it to 5V using a single supply op amp...... plz comment if there is a better solution.....
[ Edited Mon Feb 02 2009, 07:26 pm ]
Mon Feb 02 2009, 10:08 pm
use transistor as switching and you can achieve all your need by controlling base biasing (its recommended you to know potential dividing biasing ) OP-AMP can Also help in Best way for 2nd prob
also refer this link
http://www.zen22142.zen.co.uk/Design/bjtbias.htm
:-)
also refer this link
http://www.zen22142.zen.co.uk/Design/bjtbias.htm
:-)
[ Edited Mon Feb 02 2009, 10:09 pm ]
Tue Feb 03 2009, 12:04 am
kazim,
always note that when u generate a voltage source,the internal impedance of the source carries a significant part in the design and it should be very low compared to the load connected to it ( an ideal case would be zero impedance which is practically impossible). So in ur case, when u used a voltage divider, the internal impedance is significantly high. Try using a adjustable zener circuit ( a TL431 would suffice) instead of the 1k resistor in the voltage divider to generate the 4V source.
:-)
always note that when u generate a voltage source,the internal impedance of the source carries a significant part in the design and it should be very low compared to the load connected to it ( an ideal case would be zero impedance which is practically impossible). So in ur case, when u used a voltage divider, the internal impedance is significantly high. Try using a adjustable zener circuit ( a TL431 would suffice) instead of the 1k resistor in the voltage divider to generate the 4V source.
:-)
Powered by e107 Forum System